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The Batman Equation

March 20, 2017

https://www.google.com/search?hl=en&output=search&sclient=psy-ab&q=2+sqrt(-abs(abs(x)-1)*abs(3-abs(x))%2F((abs(x)-1)*(3-abs(x))))(1%2Babs(abs(x)-3)%2F(abs(x)-3))sqrt(1-(x%2F7)%5E2)%2B(5%2B0.97(abs(x-.5)%2Babs(x%2B.5))-3(abs(x-.75)%2Babs(x%2B.75)))(1%2Babs(1-abs(x))%2F(1-abs(x)))%2C-3sqrt(1-(x%2F7)%5E2)sqrt(abs(abs(x)-4)%2F(abs(x)-4))%2Cabs(x%2F2)-0.0913722(x%5E2)-3%2Bsqrt(1-(abs(abs(x)-2)-1)%5E2)%2C(2.71052%2B(1.5-.5abs(x))-1.35526sqrt(4-(abs(x)-1)%5E2))sqrt(abs(abs(x)-1)%2F(abs(x)-1))%2B0.9&pbx=1&oq=2+sqrt(-abs(abs(x)-1)*abs(3-abs(x))%2F((abs(x)-1)*(3-abs(x))))(1%2Babs(abs(x)-3)%2F(abs(x)-3))sqrt(1-(x%2F7)%5E2)%2B(5%2B0.97(abs(x-.5)%2Babs(x%2B.5))-3(abs(x-.75)%2Babs(x%2B.75)))(1%2Babs(1-abs(x))%2F(1-abs(x)))%2C-3sqrt(1-(x%2F7)%5E2)sqrt(abs(abs(x)-4)%2F(abs(x)-4))%2Cabs(x%2F2)-0.0913722(x%5E2)-3%2Bsqrt(1-(abs(abs(x)-2)-1)%5E2)%2C(2.71052%2B(1.5-.5abs(x))-1.35526sqrt(4-(abs(x)-1)%5E2))sqrt(abs(abs(x)-1)%2F(abs(x)-1))%2B0.9&&cad=h

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